Question 126632
2x+3y=6
x+2y=5 
the first thing you must do is 
cancel out the x's by adding the negative
1(2x+3y=6)
-2(x+2y=5)
you get
 2x+3y=6
-2x-4y=-10
---------
y=-4

now do the exact same with y
-2(2x+3y=6)
 3(x+2y=5)
------------
-4x+6y=-12
 3x+6y=15
------------
-x=3
since you can't have an answer with a negative x
so you move the negative sign over
so the answer is x=-3
the points are (-3,-4)

NEXT...
4x+5y=6
6x-7y=-20
you do the same with this equation
-3(4x+5y=6)
 2(6x-7y=-20)
-12x+15y=18
 12x-14y=-40
------------
y=-22
do the same with y
7(4x+5y=6)
5(6x-7y=-20)
28x+35y=42
30x-35y=-100
-------------
58x=-58
now divide 58 to both sides 
of the equation
58x/58=-58/58
x=-1

the points are
(-1,-22)
good luck!!!