Question 129227
A right triangle has a leg measuring 5 inches and a hypotenuse measuring 8 inches what is the area?


a leg measuring {{{5 in}}}
 
the area {{{A}}} of the square formed by the leg is:

{{{A = (5in)^2 = 25in^2}}}


a hypotenuse measuring {{{8 in}}} 

the area {{{A}}} of the square formed by the hypotenuse is:

{{{A = (8in)^2 = 64in^2}}}


the other leg measuring {{{xin}}}

use Pythagorean Theorem to find it:


{{{x^2 = (8in)^2 - (5in)^2}}}

{{{x^2 = 64in^2 - 25in^2}}}

{{{x^2 = 39in^2}}}

{{{x = sqrt(39in^2)}}}

{{{x = 6.25in)}}}


the area {{{A}}} of the square formed by the leg {{{x}}} is:

{{{A = (6.25in)^2 = 39in^2}}}