Question 129112
Find one where one of the legs is 37 and the hypotenuse is one more than the longer leg. 
---------------
(x+1)^2 = x^2+ 37^2
2x+1 = 37^2
2x = 1368
x = 684 (2nd leg)
x+1 = 685 (hypotenuse)
================
Cheers,
Stan H