<PRE><B>Question 128988</B>
LET X=THE AMOOUNT OF MONEY FOR THE FIRST KID.
LET 3X=THE AMOUNT OF MONEY FOR THE SECOND KID.
IF THE FIRST KID SPENDS 2/7 THEN HE HAS 5*3X/7 LEFT.
THE SECOND KIS SPENDS 3/5 THEN HE HAS 2X/5 LEFT.
5*3x/7=2x/5+122
15x/7-2x/5=122
(5*15x)+7*-2x)/7*5=122
75x-14x/35=122
61x=35*122
61x=4270
x=4270/61
x=70 for the amount of the second kid. 
3*70=210 for the first kid.
PROOF:
15*70/7=2*70/5+122
15*10=140/5+122
150=28+122
150=150
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