Question 128924
Let's evaluate f(0)


{{{f(x)=2x^2-2x}}} Start with the given function



{{{f(0)=2(0)^2-2(0)}}} Plug in {{{x=0}}}



{{{f(0)=2*0-2*0}}} Raise 0 to the 2nd power to get 0



{{{f(0)=0-2*0}}} Multiply 2 and 0 to get 0



{{{f(0)=0-0}}} Multiply 2 and 0 to get 0



{{{f(0)=0}}} Subtract 0 from 0 to get 0




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Let's evaluate f(-1)




{{{f(x)=2x^2-2x}}} Start with the given function



{{{f(-1)=2(-1)^2-2(-1)}}} Plug in {{{x=-1}}}



{{{f(-1)=2*1-2*-1}}} Raise -1 to the 2nd power to get 1



{{{f(-1)=2-2*-1}}} Multiply 2 and 1 to get 2



{{{f(-1)=2--2}}} Multiply 2 and -1 to get -2



{{{f(-1)=4}}} Subtract -2 from 2 to get 4




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Let's evaluate f(2)




{{{f(x)=2x^2-2x}}} Start with the given function



{{{f(2)=2(2)^2-2(2)}}} Plug in {{{x=2}}}



{{{f(2)=2*4-2*2}}} Raise 2 to the 2nd power to get 4



{{{f(2)=8-2*2}}} Multiply 2 and 4 to get 8



{{{f(2)=8-4}}} Multiply 2 and 2 to get 4



{{{f(2)=4}}} Subtract 4 from 8 to get 4