Question 128870


{{{8x+2y=64}}} Start with the given equation



{{{2y=64-8x}}}  Subtract {{{8 x}}} from both sides



{{{2y=-8x+64}}} Rearrange the equation



{{{y=(-8x+64)/(2)}}} Divide both sides by {{{2}}}



{{{y=(-8/2)x+(64)/(2)}}} Break up the fraction



{{{y=-4x+32}}} Reduce




So the equation is now in slope-intercept form ({{{y=mx+b}}}) where the slope is {{{m=-4}}} and the y-intercept is {{{b=32}}}