Question 128844
2y/5=3/5+2/y
-------
Multiply thru by 5y to get:
2y^2 = 3y + 10
2y^2-3y-10 = 0
y = [3 +- sqrt(9-4*2*-10)]/4
y = [3 +- sqrt(89)]/4
y = (3+sqrt(89))/4 or x = (3-sqrt(89))/4
======================
Cheers,
Stan H.