Question 128813
Let a=longer leg, b=shorter leg, c=hypotenuse
b=a-6
c=2b-6=2(a-6)-6=2a-12-6=2a-18
a^2+b^2=c^2
a^2+(a-6)^2=(2a-18)^2
a^2+a^2-12a+36=4a^2-72a+324
2a^2-60a+288=0
(a-6)(a-24)=0
a=6 not an answer in this problem.
a=24
c=2a-18
=48-18
=30 Ans.
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Ed