Question 128743
{{{x^2-5x-1=-7}}} Start with the given equation



{{{x^2-5x-1+7=0}}}  Add 7 to both sides. 



{{{x^2-5x+6=0}}} Combine like terms



{{{(x-3)(x-2)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{x-3=0}}} or  {{{x-2=0}}} 


{{{x=3}}} or  {{{x=2}}}    Now solve for x in each case



So our answer is 

 {{{x=3}}} or  {{{x=2}}} 



Notice if we graph {{{y=x^2-5x+6}}}  we can see that the roots are {{{x=3}}} and  {{{x=2}}} . So this visually verifies our answer.



{{{ graph(500,500,-10,10,-10,10,0, x^2-5x+6) }}}