Question 128655
a)


Let's find f(2)


{{{f(x)=2x^2-7x+3}}} Start with the given function



{{{f(2)=2(2)^2-7(2)+3}}} Plug in {{{x=2}}}



{{{f(2)=2*4-7*2+3}}} Raise 2 to the 2nd power to get 4



{{{f(2)=8-7*2+3}}} Multiply 2 and 4 to get 8



{{{f(2)=8-14+3}}} Multiply 7 and 2 to get 14



{{{f(2)=-6+3}}} Subtract 14 from 8 to get -6



{{{f(2)=-3}}} Add -6 and 3 to get -3



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b)


Let's find f(-3)


{{{f(x)=2x^2-7x+3}}} Start with the given function



{{{f(-3)=2(-3)^2-7(-3)+3}}} Plug in {{{x=-3}}}



{{{f(-3)=2*9-7*-3+3}}} Raise -3 to the 2nd power to get 9



{{{f(-3)=18-7*-3+3}}} Multiply 2 and 9 to get 18



{{{f(-3)=18--21+3}}} Multiply 7 and -3 to get -21



{{{f(-3)=39+3}}} Subtract -21 from 18 to get 39



{{{f(-3)=42}}} Add 39 and 3 to get 42





So you are correct.