Question 128279
A BASE=PI*R^2=3.14*6^2=3.14*36=113.04 BASE AREA.
CIRCUMFERANCE=2PI*R=2*3.14*6=37.68 
37.68*8=339.12 AREA OF THE CYLINDER SURFACE.
ASSUMING YOU WANT TO INCLUDE THE TOP & BOTTOM THEN:
2*113.04+339.12=565.2 TOTAL SURFACE AREA.