Question 128065
{{{A[0]}}}= original cost
A = current value = 12000
t = time in years = 2008 - 1998 = 10
r = rate of decrease = .04
<br>
Substituting these values into {{{A=A[0](1-r)^t}}} we have {{{12000=A[0](1-.04)^10}}}.<br>
{{{12000=A[0](.96)^10}}}<br>
{{{12000=A[0](.664832636)}}}<br>
{{{12000/.664832636=(A[0](.664832636))/.664832636}}}<br>
{{{18049.66=A[0]}}}