Question 127775
In words,
(amount of insecticide)/(water added + original solution) = .02
Let {{{w}}} = water to be added
{{{.6*11 / (w + 11) = .02}}}
{{{6.6 / (w + 11) = .02}}}
{{{6.6 = .02(w + 11)}}}
{{{6.6 = .02w + .22}}}
{{{.02w = 6.6 - .22}}}
{{{.02w = 6.38}}}
{{{w = 319}}}
319 quarts of water need to be added
check:
{{{6.6 / (w + 11) = .02}}}
{{{6.6 / (319 + 11) = .02}}}
{{{6.6 / 330 = .02}}}
{{{.02 = .02}}}
OK