Question 19341
f(x)={{{(x^2-36)/(x^2-7x+6)}}}
<br>
Factoring both the numerator and denominator,
f(x)={{{((x+6)(x-6))/((x+1)(x+6))}}}
<br>
Cancelling out the common term we are left with,
f(x)={{{(x-6)/(x+1)}}}
<br>
To understand our constraints we just need to look at our function.
Now lets look at the denominator,
we see that it is (x+1).
This means that if x is '-1',then the denominator would become (-1+1)=0.
Now division by zero is not allowed,
therefore value of x cannot be allowed to become as -1.
<br>
That is our first constraint,and as nothing else is given in the question,apparently the only one.
So our value of x should belong to Real numbers,and x should not be equal to -1.
<br>
This becomes our domain:
D={x|x belongs to R;x not equal to -1}
<P>
Hope this helps,
Prabhat