Question 127703
Lets put the equation into slope intercept form {{{y=mx+b}}} with m being the slope.

{{{6x-2y=36}}}

1.  We must isolate the y variable.  Minus 6x from both sides

{{{6x-6x-2y=36-6x}}}

Result  {{{-2y=-6x+36}}}

2.  Now divide both sides by -2

{{{(-2y)/-2=(-6x)/-2+36/2}}}

Result   {{{y=3x+18}}}

Using the slope formula we know that the slope of the original equation is {{{3/1}}}.