Question 127625
{{{x^2+4x < 2x + 8}}} Subtract 2x from both sides of the inequality.
{{{x^2+2x < 8}}} Subtract 8 from both sides.
{{{x^2+2x-8 < 0}}} Factor the trinomial.
{{{(x-2)(x+4) < 0}}} so...
{{{x-2 < 0}}} or {{{x+4 < 0}}}
{{{x-2 < 0}}} Add 2 to both sides.
{{{x < 2}}}
{{{x+4 < 0}}} Subtract 4 from both sides.
{{{x < -4}}}
The solution set looks like: [-4, 2]