Question 127506
Do you want to solve for c?




{{{4p+2c=80}}} Start with the given equation



{{{2c=80-4p}}}  Subtract {{{4 p}}} from both sides



{{{2c=-4p+80}}} Rearrange the equation



{{{c=(-4p+80)/(2)}}} Divide both sides by {{{2}}}



{{{c=(-4/2)p+(80)/(2)}}} Break up the fraction



{{{c=-2p+40}}} Reduce




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Or...


Do you want to solve for p?





{{{4p+2c=80}}} Start with the given equation



{{{4p=80-2c}}}  Subtract {{{2c}}} from both sides



{{{4p=-2c+80}}} Rearrange the equation



{{{p=(-2c+80)/(4)}}} Divide both sides by {{{4}}}



{{{p=(-2/4)c+(80)/(4)}}} Break up the fraction



{{{p=-(1/2)c+20}}} Reduce