Question 127474
{{{log(2,1/sqrt(32))}}}
writing this another way,
{{{2^x = 1/sqrt(32)}}}
{{{2^x = 1/sqrt(16*2)}}}
{{{2^x = 1/(4*(2^(1/2)))}}}
{{{2^x = 2^(-2)*2^(-1/2)}}}
{{{2^x = 2^(-2-(1/2))}}}
{{{2^x = 2^(-(5/2))}}}
{{{x = -(5/2)}}}
{{{log(2,1/sqrt(32)) = -(5/2)}}} answer