Question 127414




First convert the standard equation {{{5x-3y=12}}} into slope intercept form


*[invoke converting_linear_equations "standard_to_slope-intercept", 5, -3, 12, 2, 1]





Now let's find the equation of the line that is parallel to {{{y=(5/3)x-4}}} which goes through (-4,3)


*[invoke equation_parallel_or_perpendicular "parallel", "5/3", "-4", -4,3]