Question 127416




First convert the standard equation {{{5x-2y=10}}} into slope intercept form


*[invoke converting_linear_equations "standard_to_slope-intercept", 5, -2, 10, 2, 1]




Now let's find the equation of the line that is perpendicular to {{{y=(5/2)x-5}}} which goes through (5,-1)


*[invoke equation_parallel_or_perpendicular "perpendicular", "5/2", "-5", 5,-1]