Question 19298
{{{(16x^2-8x+1)}}}
{{{(4x)^2-8x+1}}}
{{{(4x)^2 -(2)(4)(1)x +1}}}
{{{(4x)^2 -(2)(4)(1)x + (1)^2}}}
Now this is of the form {{{(a+b)^2=a^2+2ab+b^2}}}
So we can write,
{{{(4x+1)^2}}}
<P>
-Prabhat