Question 127368
Pythagoras says that if a right triangle has legs a and b, then the hypotenuse, c, is of length {{{c=sqrt(a^2+b^2)}}}


So, for your problem, a = 1 and b = x, so just plug in the values:


{{{c=sqrt(1^2+x^2)}}}
{{{c=sqrt(1+x^2)}}}