Question 127334
Now let's graph the solution set



Start with the given inequality:


{{{x>=13/5}}}


Set up a number line:

{{{number_line(500,-5,23)}}} 


Now plot the point {{{x=13/5}}} on the number line (remember {{{13/5=2.6}}})



{{{number_line(500,-5,23, 13/5)}}}



Now pick any test point you want, I'm going to choose x=0, and test the inequality {{{x>=13/5}}}



{{{0>=13/5}}} Plug in {{{x=0}}}



Since this inequality is <font size=4><b>not</b></font> true, we simply shade the entire portion that does <font size=4><b>not</b></font> contain the point x=0 using the point {{{x=13/5}}} as the boundary. This means we shade everything to the right of the point {{{x=13/5}}} like this:

{{{drawing(500,50,-5,23,-10,10,
number_line(500,-5,23, 13/5),
blue(line(13/5,-5,13/5+20,-5)),
blue(line(13/5,-6,13/5+20,-6)),
blue(line(13/5,-7,13/5+20,-7)),
blue(arrow(13/5,-5,13/5+20.2,-5)),
blue(arrow(13/5,-5.5,13/5+20.2,-5.5)),
blue(arrow(13/5,-6,13/5+20.2,-6))
)}}} Graph of {{{x>=13/5}}} with the shaded region in blue

note: at the point {{{x=13/5}}}, there is an <font size=4><b>closed</b></font> circle. This means the point {{{x=13/5}}} is included from the solution set.