Question 127308
You're on the right track, but "five-fourths of the number" does not translate to {{{x+5/4}}}. It translates to {{{(5/4)x}}} where the {{{5/4}}} is multiplied by x. The same applies to the statement "third of the number "



So our equation should look like this:


{{{x + (5/4)x + (1/3)x =155}}}




{{{(12)(x+(5/4)x+(1/3)x)=(12)(155)}}} Multiply both sides by the LCD of 12 (the LCD is the LCM of the denominators). This will eliminate the fractions  (note: if you need help with finding the LCM, check out this <a href=http://www.algebra.com/algebra/homework/divisibility/least-common-multiple.solver>solver</a>)




{{{12x+15x+4x=1860}}} Distribute and multiply the LCM to each side




{{{31x=1860}}} Combine like terms on the left side



{{{x=(1860)/(31)}}} Divide both sides by 31 to isolate x




{{{x=60}}} Divide


--------------------------------------------------------------

Answer:

So our answer is {{{x=60}}} 



So the number is 60