Question 127226
The answer that I have come up with is: (e -1).2:
The problem is what are the exact evaluation of, (integral sign), 2xe^(x^2) dx over the intervals (0, 1). I feel this is not correct, can you verify that for me please? 

Answer: e^x^2 evaluated at 1 minus e^x^2 evaluated at 0
= e-1
----------------------
Also please, I have determined that In x is not the correct completion of the formula, (integral sign), (1/x). Is that correct, or should I do more research on this subject? 
Answer: ln(x) + C because you want the indefinite integral, and C might
always be part of the function that was differentiated to arrive at 
an answer of ln(x).
Example: The derivative of f(x) = ln(x) +2 is the same as the derivative
of f(x)= ln(x) + 5
So when you integrate ln(x) you should write ln(x)+C to cover all the 
possible constants that might be part of the answer.
-----------
It's a different story when you take the definite integral from x=a to 
x=b because you subtract out the constant that may have been part of 
the function.
================
Cheers,
Stan H.