Question 127170
(protein in soymeal) + (protein in cornmeal) divided by
(soymeal + cornmeal) = % protein in mixture
Call amount of soymeal needed {{{s}}}
Call amount of cornmeal needed {{{c}}}
{{{(.12s + .06c) / 240 = .07}}}
{{{s + c = 240}}}
{{{c = 240 - s}}}
{{{.12s + .06(240 - s) = .07*240}}}
{{{.12s + 14.4 - .06s = 16.8}}}
{{{.06s = 2.4}}}
{{{s = 40}}}
{{{c = 240 - s}}}
{{{c = 200}}}
40 pounds of soymeal should be mixed with 200 pounds of cornmeal
check answer
{{{(.12s + .06c) / 240 = .07}}}
{{{(.12*40 + .06*200) / 240 = .07}}}
{{{4.8 + 12 = .07*240}}}
{{{16.8 = 16.8}}}
OK