<PRE><B>Question 126759</B>
A ball is thrown vertically upward with an initial velocity of 100 feet per second. 
a) Determine a function h(t) that gives the height of the ball at time t seconds after it is thrown. The height function is h(t)=-16t^2+vt+h where v is the initial velocity of the ball and h is the initial height of the ball.
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If you assume the ball was thrown upward from the ground the equation is
Ans: h(t)=-16t^2+100t because h=0.
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b) how long does it take the ball to reach its maximum height? 
Maximum occurs when t = -b/2a = -100/(2*-16) = 3.125 seconds.
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c) what is the maximum height the ball reaches?
h(3.125) = -16(3.125)^2+100(3.125) = 156.25 feet
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Cheers,
Stan H.
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