Question 127156
{{{(p^2-36)/(p+6)^2}}}


Remember the factorization of the difference of two squares?


{{{a^2-b^2=(a+b)(a-b)}}}


So apply the rule:
{{{cartoon((p^2-36)/(p+6)^2,((p+6)(p-6))/((p+6)(p+6)),(cross(p+6)(p-6))/(cross(p+6)(p+6)),green((p-6)/(p+6)))}}}


{{{(p-6)/(p+6)}}}