Question 127095
f(x)=5x^2-3x+1
f(x-2)=5(x-2)^2-3(x-2)+1
f(x-2)=5(x^2-4x+4)-3x+6+1
f(x-2)=5x^2-20x+2-3x+7
f(x-2)=5x^2-23x+9
Using the quadratic equation: {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} we get:
x=4.168 & x=.43.