Question 127068
Say {{{s}}}= speed of train A
{{{s + 18}}} = speed of train B
{{{t}}} = time each one spends
train A- {{{220 = s*t}}}
train B- {{{310 = (s + 18)*t}}}
solve each one for {{{t}}}
{{{t = 220/s}}}
{{{t = 310 / (s + 18)}}}
{{{220/s = 310 / (s + 18)}}}
multiply each side by {{{s*(s + 18)}}}
{{{220(s + 18) = 310s}}}
{{{220s + 3960 = 310s}}}
{{{90s = 3960}}}
{{{s = 44}}}
{{{s + 18 = 62}}}
train A is going 44 mi/hr
train B is going 62 mi/hr
check:
{{{220/s = 310 / (s + 18)}}}
{{{220/44 = 310 / (44 + 18)}}}
{{{5 = 5}}}
OK