Question 19278
Hello There:

Do you know what the quadratic formula is?  When you have a quadratic equation set equal to zero in the form:

a*x^2 + b*x + c = 0

where you're given the values of a, b, and c, then the formula allows you to find the values of x that make the equation true.

The quadratic formula is:  x = [-b +/- sqrt(b^2-4*a*c)]/[2*a]

2*x^2 - 3*x + 1 = 0

In your problem, a = 2, b = -3, and c = 1, so just substitute these values into the formula for a, b, and c.

x = [-(-3) +/- sqrt([-3]^2 - 4*[2]*[1])]/[2*(2)]

x = [3 +/- sqrt(9 - 8)]/4

x = [3 +/- sqrt(1)]/4

x = (3 +/- 1)/4

So, there are two solutions:

x = (3 + 1)/4 and x = (3 - 1)/4

x = 4/4 and x = 2/4

x = 1 or x = 1/2

~ Mark