Question 127041


Let's denote the first point (-3,5) as *[Tex \Large \left(x_{1},y_{1}\right)]. In other words, *[Tex \LARGE x_{1}=-3] and *[Tex \LARGE y_{1}=5]


Now let's denote the second point (3,-2) as *[Tex \Large \left(x_{2},y_{2}\right)]. In other words, *[Tex \Large x_{2}=3] and *[Tex \Large y_{2}=-2]




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{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula


{{{m=(-2-5)/(3--3)}}} Plug in {{{y[2]=-2}}},{{{y[1]=5}}},{{{x[2]=3}}},{{{x[1]=-3}}}



{{{m=-7/6}}} Subtract the terms in the numerator {{{-2-5}}} to get {{{-7}}}.  Subtract the terms in the denominator {{{3--3}}} to get {{{6}}}

  

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Answer:


So the slope of the line through the points (-3,5) and (3,-2) is {{{m=-7/6}}}