Question 126824
{{{-5e^(-x)+9=6}}}


{{{-5e^(-x)=-3}}}


{{{e^(-x)=(-3)/-5}}}


Now take the natural logarithm of both sides
{{{log(e,e^(-x))=log(e,3/5)}}}


Apply {{{log(b,x^m)=m*log(b,x)}}} and {{{log(b,a/c)=log(b,a)-log(b,c)}}}
{{{-x*log(e,e)=log(e,3)-log(e,5)}}}


{{{log(e,e)=1}}} so:
{{{-x=log(e,3)-log(e,5)}}}


Finally, multiply by -1
{{{x=log(e,5)-log(e,3)}}}