Question 126690
The initial temperature occurs when t=0



{{{T(x)=60(0.79)^(t/3)+30}}} Start with the given equation




{{{T(0)=60(0.79)^(0/3)+30}}} Plug in {{{t=0}}}



{{{T(0)=60(0.79)^0+30}}} Reduce the exponent {{{0/3}}} to 0



{{{T(0)=60(1)+30}}} Raise 0.79 to the zeroth power to get 1



{{{T(0)=60+30}}} Multiply



{{{T(0)=90}}} Add




So the initial temperature is 90 degrees. So you are correct.