Question 19208
if A(1,5), B(3,-2), and C(-3,0), find the measure of the sides of triangle ABC. Then classify the triangle by it's sides.
distance between 2 points x1,y1 and x2,y2 is given by
{{{sqrt((x2-x1)^2+(y2-y1)^2)}}}
for ex.for AB , we get 
AB={{{sqrt((3-1)^2+(-2-5)^2)}}}={{{sqrt((2)^2+(-7)^2)}}}
={{{sqrt(4+49)}}}={{{sqrt(53)}}}....
AB={{{sqrt(53)}}}...........similarly
BC={{{sqrt(40)}}}...........
CA={{{sqrt(41)}}}...........
we find all sides are different and sum of squares of the 2 smaller sides is less than the square of the biggest side ..so it is a skelene acute angled triangle .