Question 126569
{{{Log(6,x) = log(6,36) - log(6,1/6)}}}
In general, {{{log(a/b) = log(a) - log(b)}}}
{{{log(6,x) = log(6,36/(1/6))}}}
{{{log(6,x) = log(6,216)}}}
Since these are equal, I can set each one equal to {{{k}}}
{{{log(6,x) = k}}}
{{{log(6,216) = k}}}
{{{6^k = x}}}
{{{6^k = 216}}}
{{{x = 216}}}