Question 126431
Given:
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{{{2*sqrt(112)}}}
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To simplify this begin by factoring 112. First step, since 112 is even divide by 2 and you have
112 = 56*2. But the 56 is even, so you can also divide it by 2 and the 56*2 then becomes
28*2*2. And since the 28 is also even, divide it by 2 and the 28*2*2 becomes 14*2*2*2.
And again, the 14 is even so divide it by 2 and the final form is 7*2*2*2*2. The 7 is a prime
number so you cannot factor it down further.
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Return to your original expression and substitute 7*2*2*2*2 for 112 and you have:
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{{{2*sqrt(7*2*2*2*2)}}}
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You can split this up into the products:
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{{{2*sqrt(7)*sqrt(2*2)*sqrt(2*2)}}}
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But {{{sqrt(2*2) = 2}}}
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Substitute 2 for each of the terms {{{sqrt(2*2)}}} and you reduce the expression to:
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{{{2*sqrt(7)*2*2}}}
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Multiply the three 2's together to get 2*2*2 = 8 and the problem reduces to:
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{{{8*sqrt(7)}}}
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So congratulations ... your answer was correct. Good job! Keep up the good work.
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