Question 126444
You are given:
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h(t) = 5 - t^2
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and you are to find h(2/3). All this is telling you to do is to go to the given function
for h(t) and for both sides wherever you see a "t" you substitute 2/3. Then you just
simplify the terms.
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In this problem you start with the function:
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h(t) = 5 - t^2
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for every t in this function you substitute 2/3 and you get:
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h(2/3) = 5 - (2/3)^2
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Next, on the right side square the 2/3 and you get 4/9. Substitute 4/9 for (2/3)^2 and
the result is:
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h(2/3) = 5 - 4/9
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Finally, subtract 4/9 from 5 [equivalent to subtracting 4/9 from 4 9/9] and you get the
answer 4 5/9 ... that's read as "4 and 5-ninths" and it's equivalent to 41/9.
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So the answer to this problem is:
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h(2/3) = 4 5/9 = 41/9
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Hope this helps you to understand the process of evaluating a function and what the notation
means. In this case h(2/3) means "find the value of h(t) when t equals 2/3."
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