Question 126341
Solve for y:


{{{x^2 + y^2 = 25}}}


{{{y^2=25-x^2}}}}


{{{y =sqrt(25-x^2)}}} OR {{{y=-sqrt(25-x^2)}}}.  The first one is the top half of the circle (all positive y values), and the other one is the bottom half of the circle, (all the negative y values).


{{{f(x)=-sqrt(25-x^2)}}}


{{{graph(400,400,-10,10,-10,10,-sqrt(25-x^2))}}}