Question 126233
The general rules are {{{log(a) - log(b) = log(a/b)}}}
and {{{a*log(b) = log(b^a)}}}
You can prove this by picking some number for {{{a}}}, say
{{{a = 7}}}, then
{{{7*log(b) = log(b*b*b*b*b*b*b)}}}
{{{7*log(b) = log(b)+log(b)+log(b)+log(b)+log(b)+log(b)+log(b)}}}
{{{7*log(b) = 7*log(b)}}}
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{{{log((x^2 - 4)) - 2*log((x + 2))}}}
{{{log((x^2 - 4)) - log((x + 2)^2)}}}
{{{log((x^2 - 4) / (x + 2)^2)}}}
{{{log(((x - 2)(x + 2)) / ((x + 2)(x + 2)))}}}
{{{log((x - 2) / (x + 2))}}} answer