Question 126227
2x-3y+z=5 -----------(1)
x+4y-2z=-3 -------------(2)
4x-2y+3z=6 --------------(3)

(2) + (1)*2 gives,    5x - 2y = 7 ------------(4)

(1)*3 - (3) gives,    2x - 7y = 9 -------------(5)

Now the equationsa are reduced to 2 in 2 variables.

(4) * 2 gives, 10x - 4y = 14
(5) * 5 gives, 10x - 35y = 45

Subtracting the above 2 equations, we get,  31 y = - 31
==> y = -1

Plugging this in (4) gives, 5x + 2 = 7
==> 5x = 7 - 2
==> 5x = 5
==> x = 1

Substituting x = 1, y = -1 in (1) , 2 + 3 + z = 5
==> 5 + z = 5
==> z = 5 - 5
==> z = 0

Thus x = 1, y = -1, z = 0

Good luck!!!