Question 126008
When a straight line equation is in the form {{{y = mx + b}}}
the slope of the line is {{{m}}}, so the 1st step is to get the
equation in that form
{{{ x - 2y + 7 = 0}}}
{{{2y = x + 7}}}
{{{y = (1/2)x + (7/2)}}}
The slope is {{{1/2}}}
Any line parallel to this line will also have {{{m = 1/2}}}
I'll start with {{{y = mx + b}}} I know what {{{m}}} is
{{{y = (1/2)x + b}}}
This line goes through (-4,0), so I'll plug this into equation
{{{0 = (1/2)*(-4) + b}}}
{{{0 = -2 + b}}}
{{{b = 2}}}
Now I know {{{m}}} and {{{b}}}
{{{y = (1/2)x + 2}}} answer