Question 125979
I'm assuming you mean: "What is the inverse of y=8x+7?"



{{{y=8x+7}}} Start with the given equation



{{{x=8y+7}}} Switch the x and y variables




{{{0=8y+7-x}}}Subtract x from both sides



{{{-8y=7-x}}} Subtract 8y from both sides



{{{y=(7-x)/(-8)}}} Divide both sides by -8 to isolate y



{{{y=(7)/(-8)-(x)/(-8)}}} Break up the fraction



{{{y=-(7/8)+(1/8)x}}} Reduce



{{{y=(1/8)x-(7/8)}}} Rearrange the terms



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Answer:

So the inverse of  {{{y=8x+7}}}  is {{{y=(1/8)x-(7/8)}}}