Question 125965
Let k = K's age now; let d = daughter's age now
:
Just write an equation for what it says:
:
"Ms K is 6 years more than 3 times as old as her daughter."
   k = 3d + 6
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8 years ago they would have been
(k-8) and (d-8)
:
"8 years ago she was 2 years less than 9 times as old as her daughter was then."
(k-8) = 9(d-8) - 2
:
k - 8 = 9d - 72 - 2
:
k = 9d - 74 + 8
:
k = 9d - 66
:
 What are their ages?
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Substitute (3d+6) for k in the above equation, find d
(3d+6) = 9d - 66
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3d - 9d = -66 - 6
:
-6d = -72
d = {{{(-72)/(-6)}}}
d = +12 yrs is the daughter's age now
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Mama would be: 36 + 6 = 42 yrs old now
:
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Check our solutions in the statement:
8 years ago she was 2 years less than 9 times as old as her daughter was then.
(42-8) = 9(12-8) - 2
  34 = 9(4) - 2; confirms out solutions
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Could you follow this OK? Any questions?