Question 125879
(X-5)/(X+4)=2/7 IF THIS IS THE EQUATION THEN WE HAVE TO CROSS MULTIPLY.
7(X-5)=2(X+4)
7X-35=2X+8
7X-2X=8+35
5X=43
X=43/5 ANSWER.
------------------------------------------
X-(5/X)+4=2/7 IF THIS IS THE EQUATION THEN:
(X^2-5)/X+4=2/7
(X^2-5)/X=2/7-4
(X^2-5)/X=(2-4*7)/7
(X^2-5)/X=(2-28)/7
(X^2-5)/X=-26/7 NOW CROSS MULTIPLY.
7(X^2-5)=-26X
7X^2-35+26X=0
7X^2+26X-35=0USING THE QUADRATIC EQUATION WE GET;
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
X=1.05 & -4.76