Question 125873


{{{(2a^2-5a)/(16a-40)}}} Start with the given expression


{{{(a(2a-5))/(16a-40)}}}   Factor {{{2a^2-5a}}} to get {{{a(2a-5)}}} 


{{{(a(2a-5))/(8(2a-5))}}}   Factor {{{16a-40}}} to get {{{8(2a-5)}}} 



{{{(a*cross(2a-5))/(8cross(2a-5))}}}  Cancel like terms




{{{a/8}}} Simplify



So {{{(2a^2-5a)/(16a-40)}}} simplifies to {{{a/8}}}



In other words, {{{(2a^2-5a)/(16a-40)=a/8}}}