Question 125852
Find the vertex and graph the quadratic function y =f(x)=6x^2-x-2 
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Vertex occurs where x= -b/2a = 1/(2*6) = 1/12
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f(1/12) = 6(1/12)^2-(1/12)-2 = -2.042
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Vertex at (1/12 , -2.042)
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Graph:
{{{graph(400,300,-3,3,-10,10,6x^2-x-2)}}}
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Cheers,
Stan H.