Question 125796
Solve for x:
1) {{{x^2-5x+6 = 0}}} Solve by factoring.
{{{(x-2)(x-3) = 0}}}
{{{x = 2}}} or {{{x = 3}}}
2) {{{2x^2-3x+1 = 0}}} Solve by factoring.
{{{(2x-1)(x-1) = 0}}}
{{{2x = 1}}}, so {{{x = 1/2}}} or {{{x = 1}}}