Question 19043
It is not necesary to change it into slope-intercept form first because it already is! Your first equation
{{{y=x+1}}}
Your Y-intercept is 1
Slope is also 1
{{{graph(300,200,-5,5,-5,5,x+1)}}}


Your second equation
Your Y-Intercept is 0
Slope is 3
{{{graph(300,200,-5,5,-5,5,3x)}}}
Hope this helps!