Question 125760
sqrt(3x+8)+4=6
sqrt(3x+8)=6-4
sqrt(3x+8)=2 now square both sides of the equation
3x+8=2^2
3x+8=4
3x=4-8
3x=-4
x=-4/3 answer.
proof
sqrt(3*-4/3+8)+4=6
sqrt(-4+8)+4=6
sqrt(4)+4=6
2+4=6
6=6
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first we find the x & y distances between these two coordinates:
x=4-1=3
y=3+3=6 
so we have a right triangle with the 2 sides = to 3 & 6.
using the pythagorean theorum 
a^2+b^2=c^2 c being the hypotenuse or distance between these two points.
362+662=c^2
9+36=c^2
45=c^2
c=sqrt45
c=6.7 is the distance.